A ship sends ultrasound that returns from the sea bed and is detected after 3.42 sec. If the speed of ultrasound through sea water is 1531 m/s. What is the distance of the sea bed from ship.
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time for the ultrasonic sound to hit the sound bed and return back is 3.42sec.
so the time taken to reach the sea bed is 3.42/2
t1=1.71sec.
so the distance covered d=v*t
d=1531*1.71
d=2618.01m
so the time taken to reach the sea bed is 3.42/2
t1=1.71sec.
so the distance covered d=v*t
d=1531*1.71
d=2618.01m
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