A Ship starts sailing in sea from Coast A to Coast B. It covers three fourth of the total distance on first day, three fourth of the remaining distance on the the second day, and the three fourth of the remaining distance on the third day. Now the ship is only 100 kms far from the Coast B. Find out the total distance travelled by the ship in three days.
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Answer:
6400 km is the total distance travelled
Step-by-step explanation:
Let the distance bw a and b be x
1st day - 3x/4
2nd day - three fourth of x/4 i.e. 3x/16
3rd day - three fourth of x/16 i.e. 3x/64
now,
3x/4 + 3x/16 + 3x/64 +100 = x
on solving you get
x = 6400 km
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