Physics, asked by ejazh1047, 8 months ago

A ship whose hull length is 100 m is to travel at 10
m/sec. For dynamic similarity, at what velocity
should a 1:25 model be towed through water ?​

Answers

Answered by rinayjainsl
0

Answer:

The model ship should be towed at an velocity of 2m/s

Explanation:

Given data.

Prototype

Length of the ship=100m

Velocity with which it travels=10m/s

Model

To find length of the model ship,we use scale ratio.

Scale ratio is given as 1:25

Therefore

 \frac{L_{m}}{L_{p}}  =  \frac{1}{25}

Substituting given data,we get

L_{m} =  \frac{1}{25}  \times 100 = 4m

Similarly to find velocity we use a non dimensional number called froude number

Fr =  \frac{v {}^{2} }{gL}

Considering dynamic similarity,we get

(\frac{v {}^{2} }{gL} ) _{m} = (\frac{v {}^{2} }{gL} ) _{p}

Substituting given values,we get

v _{m} {}^{2}  = 4   \times \frac{10 {}^{2} }{100}  =  > v _{m} = 2ms {}^{ - 1}

Therefore,The model ship should be towed at an velocity of 2m/s

#SPJ2

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