Question

A water glass sitting on a table weighs 4N . The bottom of the water glass has a surface are af 0.003m².Calculate the pressure exerted by glass of water on the table.​

Answer 1

Answer:

Pressure = Force/ Area

Explanation:

Pressure exerted by the glass

• = 4N / 0.003 m^2
• = 1333.333 N/ m^2

Answer 2

Given :

• Weight of the glass sitting on table = 4 N

• Surface area of Glass = 0.003 m²

To find :

• Pressure exerted by glass on table

Solution :

The relation between Pressure , Force and area is given by ,

$\boxed {\rm{P = \frac{F}{A} }}$

We have ,

• Weight of the glass = 4 N = Force exerted by glass on table
• Area of glass = 0.003 m²

By substituting the values ,

$\displaystyle : \implies \rm \: P = \dfrac{4 \: N}{0.003 \: m {}^{2} } \\ \\ : \implies \rm \: P = \frac{4}{0.003} \: Nm {}^{ - 2} \\ \\ : \implies \rm \: P = \frac{4}{3 \times {10}^{ - 3} } \: Nm {}^{ - 2} \\ \\ : \implies \rm \: P = \frac{4 \times 10 {}^{3} }{3} \: Nm {}^{ - 2} \\ \\ : \implies \rm \: P = \frac{4 \times 1000}{3} \: Nm {}^{ - 2} \\ \\ : \implies \rm \: P = \frac{4000}{3} \: Nm {}^{ - 2} \\ \\ : \implies \rm \: P = 1333.3 \: Nm {}^{ - 2}$

∴ The pressure exerted by the glass on table is 1,333.3 N/m²