Question

a shop owner blends three types of tea,A,B,C in ratio 6:4:7.if the mass of tea C in the mixture is 28kg, find the difference in the masses of the other two types of tea.

Answer 1

 ratio of three types of tea=6:4:7
sum of the ratio=6+4+7=17
mass of  c in the mixture = 28 kg
∴total mass of tea in the mixture = (17 × 28)/7
⇒ 476/7=68Kg 
mass of a=(6 × 68)/17=24 Kg
mass of b =(4 × 68)/17=16 Kg
∴difference between a and b tea=24-16=8Kg

Answer 2

A would be 6/7 x 28kg = 24 kg
B would be 4/7 x 28kg = 16 kg
so the difference of the masses is
24 - 16 = 8kg