Question

a shope keeper sells 3 pen and 4 pencil @22 rupees he sells 4 pen and 3 pencil @27 rupees find the selling price of one pen and one pencil​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

The selling price of one pen is Rs.6

The selling price of one pencil is Rs.1

Step-by-step explanation:

A Shopkeeper sells 3 pens and 4 pencils for 22 rupees

A Shopkeeper sells 4 pens and 3 pencils for 27 rupees

let pens be x

pencils= y

3x+4y=22==>1

4x+3y=27==>2

Here, we cannot apply elimination method

Using Substitution method

3x+4y=22

3x=22-4y

$x=\frac{(22-4y)}{3}$   ==>3

Substitute equation 3 in 2

$\frac{4}{3} (22-4y)+3y=27$

$\frac{4}{3} (22-4y)+\frac{9y}{3} =27$

$4 (22-4y)+9y=27(3)$

$4 (22-4y)+9y=81$

$88-16y+9y=81$

$88-81=16y-9y$

$7=7y$

$7y=7$

$y=1$

substitute the value of y in equation 3

$x=\frac{(22-4(1))}{3}$

$x=\frac{22-4}{3}$

$x=\frac{18}{3}$

$x=6$

The selling price of one pen is Rs.6

The selling price of one pencil is Rs.1