Question

A shopkeeper bought 20 kg of tea at ₹ 60 per kg .he sold 5 kg at 72 per kg 8 kg at ₹ 70 per kg and rest at ₹ 55 per kg . find his loss or profit percent

Answer 1

Solution :-
Cost Price for 1 kg of tea = ₹60
Therefore Cost Price for 20 kg of tea = ₹(60×20)
=₹1200

Next:-
SP of 1 kg of tea = ₹72
Therefore SP of 5 kg of tea = ₹(72×5)
= ₹360
SP of 1 kg of tea = ₹70
Therefore SP of 8 kg of tea = ₹(70×8)
= ₹560

Remaining quantity of tea=20-(8+5)kg
= 20-13 kg
= 7 kg

SP of 1 kg of tea = ₹55
Therefore SP of 7 kg of tea = ₹(55×7)
= ₹385
Therefore total SP of tea by the shopkeeper = ₹(360+560+385)
= ₹1350
Now:-
Profit = Total SP - Total CP
= ₹(1305 - 1200)
= ₹105
Therefore Profit%=(Profit / CP) × 100%
= (105 / 1200) ×100%
= 0.0875 × 100 %
= 8.75 % (Answer)

Answer 2

Step-by-step explanation:

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