Question

A shopkeeper bought 20kg of tea at rs.60 per kg he sold 5kg at rs.72 per kg 8kg at rs.70 per kg and rest at rs.55 per kg find his loss or profit per cent

Answer 1

CP of 20 kg of tea at rs. 60 per kg= 60×20=1200
SP of 5 kg tea at rs. 72 per kg=
72×5=360

Answer 2

The shopkeeper earns a profit of 8.75%

Cost Price (C.P) of 1 kg of tea for shopkeeper = Rs 60

So, C.P of 20kg of tea = Rs (60×20) = Rs 1200

He sold 5kg at rs.72 per kg

Selling Price (S.P.) of 1 kg tea = Rs 72

So, S.P of 5kg tea = Rs (5×72) = Rs 360

He sold 8kg at rs.70 per kg

S.P of 1 kg tea = Rs 70

So, S.P. of 8kg of tea = Rs (70×8) = Rs 560

He sold the rest at rs.55 per kg

Remaining tea left = 20kg - (5+8)kg = 20 - 13 = 7kg

S.P of 1 kg = Rs 55

So, SP of 7kg of tea = Rs (7×55) = Rs 385

So, total SP of 20kg tea = Rs (360 + 560 + 385) = Rs 1305

Since, SP>CP , he earns profit.

Profit value = SP-CP = Rs ( 1305-1200) = Rs 105

Profit% = [(Profit value)/CP] × 100%] = 8.75%