A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 8% of bananas were rotten. Find the percentage of fruits in good condition.
Answers
total fruits are 1000(600 oranges and 400 bananas)
(85%oranges +92%bananas) +(15% oranges + 8% oranges) = 1000
we have to find the value of (85%oranges +92%bananas)
85%oranges= 85/100*600
= 510 oranges
92%bananas = 92/100*400
= 368 bananas
total nice fruits are 878
% nice fruits = (878/1000)*100
= 87.8%
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Step-by-step explanation:
Total no. of fruits shopkeeper brought =600+400=1000
no. of rotten orange= 600×15/100= 90
no. of rotten bananas=400×8/100=32
Therefore, total no. of rotten fruit =90+32=122
no. of fruits in good condition =1000-122=878
% of fruit in good condition =
878/1000×100=
878/10= 87.8%