Question

A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 8% of bananas were rotten. Find the percentage of fruits in good condition?

Answer 1

15/100×600=90 orange
8/100×400=32 bananas are rotten
remaining is 510 , 368
initially total =1000
now =510+368=878
878/1000×100= 87.8% is in good condition

Answer 2

Answer:

87.8% fruits are in good condition.

Step-by-step explanation:

Number of oranges = 600

Number of bananas = 400

Total number of fruits = 600 +400 = 1000

15% of oranges were rotten. Thus, number of rotten oranges is given by

600×0.15

= 90

Also, 8% of bananas were rotten. Thus, number of rotten bananas is given by

400×0.08

= 32

Hence, total number of rotten fruits = 90 + 32 = 122

Thus, number of fruits in good conditions = 1000 - 122 = 878

Therefore, percentage of fruits in good condition is

$\frac{878}{1000}\cdot100\\\\=87.8\%$

Hence, 87.8% fruits are in good condition.