a circle is inscribedin a triangle ABC touching BC, CA and AB,at p, q and R respectively if a b is 10 cm aqis equal 7 cm cq
is equal 5 cm find BC
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we know that tangent from a exterior point are equal in length
therefore AQ=AR=7cm (A IS POINT)
BR=BP
AND. PC=CQ=5cm
now BR=AB-AR
BR=10-7=3
ALSO BC=BP+PC=3+5=8CM
therefore AQ=AR=7cm (A IS POINT)
BR=BP
AND. PC=CQ=5cm
now BR=AB-AR
BR=10-7=3
ALSO BC=BP+PC=3+5=8CM
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