Math, asked by jerry2660, 1 year ago

A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 8% of bananas were rotten. Find the percentage of fruits in good condition.A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 8% of bananas were rotten. Find the percentage of fruits in good condition.

Answers

Answered by sailokesh0904
13

number of oranges = 600

rotten oranges = 15/100 x 600 = 90 oranges

healthy oranges = 510 oranges

number of bananas = 400

rotten bananas = 8/100 x 400 = 32 bananas

healthy bananas = 358 bananas

fruits in good condition = 510 + 358 = 868 fruits

Answered by pudisai64
13

Answer:

oranges 600

bananas 400

let we see the question in he ask the find percentage of fruits in good condition

total oranges 600*15/100=90

total bananas 400*8/100=32

fruits in good condition

oranges 368

bananas 510

we add both oranges and bananas

368+510=870/100=87.8%

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