Question

A shopkeeper bought two fans for rupees 5000 he sold one at profit of 10% and the other at a loss of 10% If the SP of both hands are equal find the cost price of each fan​

Answer 1

Answer:

2500

Step-by-step explanation:

First 10% loss and 10%profit get cancelled the divide by 2

Answer 2

Let the CP to be Rs x

So, the CP of other fan will be Rs(5000-x)

Given that he sold one at a profit of 10%

So, using Profit% = $\frac{profit}{cp} \times 100$

$10 = \frac{profit}{x} \times 100$

$profit = \frac{x}{10}$

So, SP of 1st fan

$= x + \frac{x}{10} = \frac{11x}{10}$

(SP = CP+profit)

Also, given that he sold the other at loss of 10%

So, using loss% $= \frac{loss}{cp} \times 100$

$10 = \frac{loss}{(5000 - x)} \times 100$

$loss = \frac{(5000 - x)}{10}$

SP of 2nd fan

$= (5000 - x) - \frac{(5000 - x)}{10}$

As given in the question,

both the SP are same

So,

$\frac{11x}{10} = (5000 - x) - \frac{(5000 - x)}{10}$

$\frac{11x}{10} = \frac{50000 - 10x - 5000 + x}{10}$

$11x = 45000 - 9x$

$20x = 45000$

$x = 2250$

So, 5000-x

= 5000-2250

= [2750]

=[2250]

SOLVED BY √√√ ρяเýลиรђµ