Question

write four solutions of the equation 3x+4y=1​

Answer 1

Answer:

Given equation is 3x+4y=7

If x=1 put in equation we get

(i)3×1+4y=7

⇒3+4y=7

⇒4y=7−3

⇒4y=4

⇒y=1

(1,1)

If x=2 put in equation we get

(i)3×2+4y=7

⇒6+4y=7

⇒4y=7−6

⇒4y=1

⇒y=$\frac{1}{4}$

(2,$\frac{1}{4}$)

If x=3 put in equation we get

(iii)3×3+4y=7

⇒9+4y=7

⇒4y=7−9

⇒4y=−2

⇒y=−$\frac{2}{4}$

⇒y=−$\frac{1}{2}$

(3,−$\frac{1}{2}$)

If x=4 put in equation we get

iv)3×4+4y=7

⇒12+4y=7

⇒4y=7−12

⇒4y=−5

⇒y=−$\frac{5}{4}$

(4,−$\frac{5}{4}$)

Hope this answer helps you out.