Question

A shopkeeper bought two items at 450 is he sold one at loss of 10% and what price should he sell the other as to gain 20% on the whole transaction​

Answer 1

Given:

A shopkeeper bought two items at 450 each

He sold one item at 10% loss

To find:

At what price should he sell the other as to gain 20% on the whole transaction​?

Solution:

Let "x" represents the selling price of the other item.

The total cost price of the two items = Rs. 450 × 2 = Rs. 900

We will use the following formula:

$\boxed{\bold{S.P. = \frac{100 - L\%}{100}\times C.P. }}\\\\\boxed{\bold{S.P. = \frac{100 + G\%}{100}\times C.P. }}$

Using the above formula, we get,

∴ The S.P. of the first item is,  

= $\frac{100 - 10}{100} \times 450$

= $\frac{90}{100}\times 450$

= $0.9\times 450$

= $Rs.\:405$

and

∴ The total S.P. of the two items is,

= $\frac{100 + 20}{100} \times 900$

= $\frac{120}{100}\times 900$

= $1.2\times 900$

= $Rs.\:1080$

Now,

The S.P. of the other item should be,

= [Total S.P. of the two items] - [S.P. of the first item]

= [Rs. 1080] - [Rs. 405]

= Rs. 675

Thus, the shopkeeper should sell the other at Rs. 675 so as to gain 29% on the whole transaction.

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Answer 2

Answer :-675 ₹

Step-by-step explanation:

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