Math, asked by siddharth426, 11 months ago

A shopkeeper buys 100 cricket balls for 10000 rupees and sells 40 of them at a profit of 12.5% at what percent should he sell the remaining Ball So that overall profit is 20%

Answers

Answered by RohitSaketi
25
A shopkeeper buys 100 cricket balls for 10000 rupees

Total Cost = 10000

No.of balls = 100

Then the cost of each ball will be

= TotalCost / No.of balls

= 10000/100

=100 rupees each

sells 40 of them at a profit of 12.5%

selling price -

= cost price + profit

cost price -

=No.of balls × cost of each ball

= 40 balls × 100rs = 4000

Profit-

= cost price × profit percentage

= 4000 ×12.5%

=4000 × 12.5/100

=500

Selling Price = 4000 + 500 = 4500


at what percent should he sell the remaining Ball So that overall profit is 20%


Cost of 100 balls = 10000

Profit Percentage Required = 20%

Selling price will be =

cost price + profit


Profit:-

= cost price × Profit Percentage

= 10000 × 20%

=10000 × 20/100

=2000

Final selling price:-

= 10000 + 2000

=12000


Amount already in hand = 4500

Required sales = 12000 - 4500 = 7500

cost price of 60 balls

= 60 ×100

=6000

Profit :-

= selling price - cost price

=7500 - 6000

=1500

Profit Percentage :-

= (Profit/cost price) × 100

= (1500/6000) × 100

=150000/6000

=25% is the answer
Answered by Samanwita
19
Shop keeper buys 100 balls for 10000

Then the cost of one ball = 10000 / 100 = 100

He sells 40 balls at 12.5%

(40 × 100)+ 12.5%(profit)

4000 + 12.5%

4000 + 12.5×4000/100

4000 + 500

4500


overall profit required= 20%

cost price= 10000

profit = cost × profit rate = 10000×20% = 2000

Selling price= 10000 + 2000 = 12000


estimated selling price - partial sale amount

12000 - 4500 = 7500 = required amount

cost of remaining balls = 60 × 100 = 6000

Profit = Required amount - cost = 7500 - 6000 =1500

profit Percentage= (profit/cost price)×100 = (1500/6000)×100 = 150000/6000 = 25%


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