Question

A shopkeeper buys 3 varieties of rice for Rs 20, Rs 30 and Rs 40 per kg respectively. He now mixes the 3 varieties in the ratio 5:6:7 by weight and sells the mixture at a profit of 10%. What price does he sell it for?
A.40(8/9)
B.38(4/9)
C.34(2/9)
D.30(2/9)

Answer 1

first we have to find average price

5 kg of Rs.20 =100

6kg of Rs. 30=180

7kg of Rs 40=280

total price =560

average or c. p of 1kg mixture =560/18=280/9

s. p=280/9*110/100=34.22

Answer 2

Given:

A shopkeeper buys 3 varieties of rice for Rs 20, Rs 30 and Rs 40 per kg respectively.

He mixes the 3 varieties in the ratio 5:6:7 by weight.

He sells the mixture at a profit of 10%.

To find:

The price of the three varieties of rice mixture sold by the shopkeeper.

Solution:

A shopkeeper buys 3 varieties of rice for Rs 20, Rs 30 and Rs 40 per kg respectively.

He mixes the 3 varieties in the ratio 5:6:7 by weight.

Total weight = 5 + 6 + 7

Total weight = 18

5kg of Rs 20 is 5 × 20 = Rs 100

6kg of Rs 30 is 6 × 30 = Rs 180

7kg of Rs 40 is 7 × 40 = Rs 280

Total price = 100 + 180 + 280

Total price = Rs 560

Cost price of 1kg mixture = $\frac{560}{18}$

Cost price of 1kg of mixture = $\frac{280}{9}$

He sells the mixture at a profit of 10%.

Selling price = $\frac{100+Profit }{100}$ × Cost price

Selling price = $\frac{100+10}{100}$ × $\frac{280}{9}$

Selling price = $\frac{110}{100}$ × $\frac{280}{9}$

Selling price = $\frac{308}{9}$

Selling price =  $34\frac{2}{9}$

Final answer:

The price of the three varieties of rice mixture sold by the shopkeeper

is $34\frac{2}{9}$

Thus, the correct option is C.34(2/9)