Math, asked by ashketchum085, 1 year ago

A shopkeeper buys a box of 10 dozen apples for Rs.180.He estimates that 20% of them would be rotten.He intends to sell each apple so as to make a profit of 60% on his cost.Assuming that 20% of the apples turn out to be rotten.Find:
i) the number of good apples in the box
ii)the sum of money for which he should sell the good apples so as to make a profit of 60% on his cost.
iii)the selling price of each apple in order to earn the said profit.
plz plz fast

Answers

Answered by ahmad131
1
numbers of apple = 20 ÷100 × 120 - 120 = 96
cp of apples = 180
therefore sp = 160÷100×180 = 288
therefore cost of 1 apples = 2.4 ruppees
Answered by NehaKari
1

Given :

Shopkeeper buys 10 dozen apples for Rs.180

% of apples estimated to be rotten = 20%

% of profit he wants to make = 60%

To Find :

(i) The number of good apples in the box

(ii) The sum of money for which he should sell the good apples so as to make a profit of 60% on his cost.

(iii) )the selling price of each apple

Solution :

(i) Given, 20% of the apple turned out to be rotten.

  He bought 10 dozens of apple

  Total no. of apple that he bought = 10 × 12 = 120

Now, Number of rotten apples = 20% of 120 = 24

∴ Number of good apples = (120 - 24) = 96

(ii) He bought apples for Rs. 180

    Profit that he should make to gain a profit of 60% = 60% of 180 = Rs. 108

∴ The sum of money for which he should sell the good apples so as to       make a profit of 60% = (180 + 108) = Rs. 288

(iii) Number of good apples = 96

     The amount for which he should sell the apples to gain 60% profit = 288  

     Therefore, Selling Price of each apple = \frac{288}{96}

                                                                      = 3

∴ The selling price of each apple in order to earn 60% profit is Rs. 3

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