A shopkeeper earns a profit of ₹20 by selling a notebook and incurs a loss of ₹5 by selling a pen. On a particular day ,the shopkeeper sold 6 notebooks and incurred a loss of ₹150 .How many pens did the shopkeeper sell that day ?Find his net profit or loss.
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Answers
Answer
A shopkeeper earns a profit of Re 1 by selling one pen and incurs a loss of 40 paise per pencil while selling pencils of her old stock. In a particular month she incurs a loss of Rs. 5 In this period, she sold 45 pens. How many pencils did she sell in this period?
ANSWER
Profit earned by selling 1 pen = Re 1
Profit earned by 45 pens = Rs. 45, which we denote by + Rs. 45
Total loss given = Rs. 5, which we denote by Rs -5.
Profit earned + Loss incurred = Total Loss
Therefore, loss incured = Total Loss - Profit earned.
= Rs. (-5-45)
=Rs. (-50)= -5000 paise
Loss incurred by selling one pencil = 40 paise, which we write as -40 paise.
So, number of pencils sold = (−5000)÷(−40)=125 pencils.
Answer:
30 ; loss of rs 30
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