Math, asked by ManaswithaManu, 1 month ago

A shopkeeper earns a profit of Rs 2 by selling a pen and incurs a loss of 50 paise per pencil and

loss of 15 paise per eraser while selling pencils and erasers of old stock . On a particular day, he

earns a profit of Rs 10 .If he sold 10 pens and the number of pencils and erasers he sold are in the

ratio 7:10

1. How many erasers are sold by the shopkeeper ?

a) 60 b) 30 c ) 20 d) 10

2. How many pencils are sold by the shopkeeper ?

a) 13 b) 18 c) 16 d) 14

3. Total how much loss the shopkeeper has got on selling pencils and erasers ?

a) 700paise b) 300 paise c)800paise d)Rs10/-

4. How much gain the shopkeeper has got by selling pens ?

a) RS 20/- b) Rs 30/- c )Rs 40/- d)Rs19/-

5.What is the ratio of PENS, PENCILS, ERASERS sold by the shopkeeper

a) 7:10:5 b) 5:7:10 c) 10:7:5 d) NONE​

Answers

Answered by nandakish2009
0

Answer:

By selling a pen gain is Rs.2

and by selling a pencils, he loses 50 paise

and an eraser, he loses 15 paise

On one day, he gain =Rs.10

On that day he sold 10 pens and pencils and erasers in the ratio of 7:10

On ten pens, his gain =10×2=Rs.20

loss on pencils and erasers =Rs.20−Rs.10=Rs.10=1000 paise

Ratio in pencil and eraser =7:10

Let number of pencils =7x, then eraser =10x

7x×50+10x×15=1000

⇒350x+150x=1000

⇒500x=1000

⇒x=2

Numbe rof penciles =7×2=14

and number of erasers =10×2=20

Step-by-step explanation:

Answered by Itsmeshefallimaansi
0

Answer:hope this helps u mate

pls amrk as brainliest and push the thanks button tooo

Step-by-step explanation:

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