Math, asked by minnajasmine3, 3 months ago

A shopkeeper gives books on rent for reading. She takes a fixed charge for the first two days, and

an additional charge for each day thereafter. Reema paid . 22 for a book kept for six days, while

Ruchika paid . 16 for the book kept for four days. Represent the given situation through a pair of

linear equation.​

Answers

Answered by itzheartkiller48
2

Answer:

Let the fixed charge be x and additional charge be y per day both in Rs.

For Latika, number of days =6=2+4

Therefore, charge x+4y=22

⇒x=22−4y ....(1)

For Anand, number of days =4=2+2

Therefore, charge =x+2y=16

⇒x=16−2y ....(2)

Comparing (1) and (2), we have

22−4y=16−2y

⇒y=3

Substituting this value of y in equation (1), we have

x=22−4×3=10

So, fixed charge = Rs. 10

and additional charge = Rs. 3 per day.

Answered by Anonymous
3

Answer:

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Step-by-step explanation:

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