A shopkeeper has 30 kgs of wheat, a part of
which he sells at 16% profit and the rest at
6% profit. He gains 10% on the whole quantity.
Find the quantity sold at 6% profit.
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Answer:
he sold 25•2 kgs at 6%
Step-by-step explanation:
total amount of wheat the shopkeeper had=30 kgs
profit in % for the first part=16%
profit in % for the second part=6%
profit in % for the entire quantity of wheat=10%
let the first part be x
let the second part be y
therefore x+y=30 kgs
therefore x/30 ×100=16
x=16×30/100
x=480/100
x=4.8 kgs
y=30-x... (since x+y=30)
y=30•0-4•8
y=25•2 kgs
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