A shopkeeper has 6 ticket in a box . 2 ticket among them are worth a prize of rupees 10 and the remaining ticket are worth a prize of rupees 5 if ticket is drawn at random from the box find expected value
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total no of favorable outcome of ticket =6
favourable outcome getting ₹10 ticket=2
p(getting ₹ 10)=6/2=3
favourable outcome getting ₹5=4(6-2)
p(getting ₹5)=6/4=3/2
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