A shopkeeper purchased 90 pens and the cost price of each pen is Rs 10/- and he sold it in two parts,the first part at 20% profit,and sold the second part at 10% profit.If he sold all 90 pens at certain price and got 15% profit,then the difference in profits from both the conditions is Rs.40/-,Find how many pens were sold at 20% profit??
Answers
Answer :
No. of pens sold at 20% profit = 85
Solution :
Given,
No. of pens = 90
Cost of each pen = 10/-
Total cost of 90 pens, CP = 900/-
Let, Cost price of second part be 'x'.
Case 1 :
First part is sold at 20% profit,and the second part at 10% profit
First part :
20% profit
20 = G/(900-x) × 100
⇒ Profit = (900 - x)/5
Second part :
10% = G/x × 100
⇒ Profit = x/10
Case 2 :
If pens are sold at 15% profit
15 = G/900
⇒ Profit = 135/-
According to the problem,
⟶ [(900-x)/5 + x/10] - 135 = 40
⟶ 1800 - 2x + x = 175 × 10
⟶ x = 50
Therefore, CP of second part is 50/-
CP of first part is (900 - x) = 900 - 50 = 850/-
➜ No. of pens in first part = CP/cost of each pen
= 850/10
= 85
Answer:
No. of pens sold at 20% profit = 85
Solution :
Given,
No. of pens = 90
Cost of each pen = 10/-
Total cost of 90 pens, CP = 900/-
Let, Cost price of second part be 'x'.
Case 1 :
First part is sold at 20% profit,and the second part at 10% profit
First part :
20% profit
20 = G/(900-x) × 100
⇒ Profit = (900 - x)/5
Second part :
10% = G/x × 100
⇒ Profit = x/10
Case 2 :
If pens are sold at 15% profit
15 = G/900
⇒ Profit = 135/-
According to the problem,
⟶ [(900-x)/5 + x/10] - 135 = 40
⟶ 1800 - 2x + x = 175 × 10
⟶ x = 50
Therefore, CP of second part is 50/-
CP of first part is (900 - x) = 900 - 50 = 850/-
➜ No. of pens in first part = CP/cost of each pen
= 850/10
= 85