Math, asked by nalanagulajagadeesh, 6 months ago

A shopkeeper purchased 90 pens and the cost price of each pen is Rs 10/- and he sold it in two parts,the first part at 20% profit,and sold the second part at 10% profit.If he sold all 90 pens at certain price and got 15% profit,then the difference in profits from both the conditions is Rs.40/-,Find how many pens were sold at 20% profit??​

Answers

Answered by yashaswini3679
9

Answer :

No. of pens sold at 20% profit = 85

Solution :

Given,

No. of pens = 90

Cost of each pen = 10/-

Total cost of 90 pens, CP = 900/-

Let, Cost price of second part be 'x'.

Case 1 :

First part is sold at 20% profit,and the second part at 10% profit

First part :

20% profit

20 = G/(900-x) × 100

⇒ Profit = (900 - x)/5

Second part :

10% = G/x × 100

⇒ Profit = x/10

Case 2 :

If pens are sold at 15% profit

15 = G/900

⇒ Profit = 135/-

According to the problem,

⟶ [(900-x)/5 + x/10] - 135 = 40

⟶ 1800 - 2x + x = 175 × 10

⟶ x = 50

Therefore, CP of second part is 50/-

CP of first part is (900 - x) = 900 - 50 = 850/-

➜ No. of pens in first part = CP/cost of each pen

= 850/10

= 85

Answered by ayushbag03
5

Answer:

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No. of pens sold at 20% profit = 85

Solution :

Given,

No. of pens = 90

Cost of each pen = 10/-

Total cost of 90 pens, CP = 900/-

Let, Cost price of second part be 'x'.

Case 1 :

First part is sold at 20% profit,and the second part at 10% profit

First part :

20% profit

20 = G/(900-x) × 100

⇒ Profit = (900 - x)/5

Second part :

10% = G/x × 100

⇒ Profit = x/10

Case 2 :

If pens are sold at 15% profit

15 = G/900

⇒ Profit = 135/-

According to the problem,

⟶ [(900-x)/5 + x/10] - 135 = 40

⟶ 1800 - 2x + x = 175 × 10

⟶ x = 50

Therefore, CP of second part is 50/-

CP of first part is (900 - x) = 900 - 50 = 850/-

➜ No. of pens in first part = CP/cost of each pen

= 850/10

= 85

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