Question

A shopkeeper purchased two radios at Rs. 1008, and he sold one at a loss of 20% and the other at a profit of 44%. If he sell both radios at the same price, then what is the cost price of the radio which is sold at a loss?​

Answer 1

Answer:

648.

Step-by-step explanation:

Consider, the cost price of the radio 1 is x and it is sold at a loss and cost price of radio 2 is y and it is sold at profit.

So, x+y =1008 …………. (1)

Selling price of radio 1 is = x- 20% x = (80/100)x

Selling price of radio 2 is = y + 44%y = (144/100)y

So, (80/100)x = (144/100)y

80x - 144y = 0 …………………..(2)

Multiplying (1) by 144 and adding (1) and (2),

(144 + 80)x = 1008 * 144

x= (1008*144)/ 224 = 648

y = 1008 -648 = 360

So, the cost price of the radio which is sold at loss is 648.

Answer 2

C.P of 2 radio =1008

LOSS% =20%

LOSS =20/100×1008

LOSS =211.6

S.P of 2 radio = C.P - LOSS

S.P = 1008 - 211.6

S.P = 796.4