Math, asked by xiiaoyi6776, 1 year ago

A shopkeeper purchased two watches for a total of re 2160. By selling one at a loss of 9% and other at a gain of 15%, he neither gains nor loss in the whole transaction. Find the cost price of each watch. ,

Answers

Answered by munmunmajumdar
37

A shopkeeper purchased two...

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Answered by amikkr
14

Cost price of watches are Rs. 1350 and Rs. 810

  • Let the cost price of watch A be x.
  • Total cost price of watch A + cost price of watch B is Rs. 2160.
  • On selling a watch he suffers a loss of 9%.

Therefore, Loss = 0.09x

  • Now cost price of watch B will be (2160-x).
  • On selling watch B he gains a profit of 15%.

Therefore, 15 = \frac{profit}{cost \ price} × 100

15 = \frac{profit}{2160-x} × 100

profit = \frac{15(2160-x)}{100}

  • Now on selling both the watches he neither gains nor loss in the whole transaction.
  • Therefore the loss on watch A = profit on watch B

0.09x = \frac{15(2160-x)}{100}

9x = 32400 - 15x

x = 32400/24

x = 1350 Rs.

  • Cost price of watch A is Rs. 1350
  • Cost price of watch B is Rs. 810.
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