Math, asked by pullbrothe, 9 days ago

a shopkeeper sells 60% of the pens he had still has 120 pens left . the total number of pens he had in all is?​

Answers

Answered by piyush000880
2

Answer:

Let the total

no. Pen sold = 60% of of pens bu u n vremaining pens - (100-60). / = 0) / = 40%.

.. of remaining 90% on хи ५० pens = 120 = 120 = 120

(0x)/5 = 120 n = (20s)/2

x = 300 Twofal no. of pens ans. = 300 pens...

Step-by-step explanation:

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Answered by knand3789
1

Answer:

Let us assume that he sells x pens for a profit of 12% and hence (60−x) pens at a loss of 8%

Let C.P of a pen be Rs.1.

Profit Loss

CP=x CP=60−x

P%=12%L%=8%

SP=CP(

100

100+P%

)SP=(60−x)(

100

100−8

)

SP=x(

100

100+12

)=

100

92(60−x)

=

100

112x

=

25

28x

25

23(60−x)

Overall

CP=x+60−x=60.

SP=

25

28x+23(60−x)

=

25

1380+5x

P%=

5.60

x−24

×100=11

3

x−24

=11

x−24=33⇒x=24+33=57

Hence 57 pens were sold at a profit 12%

Step-by-step explanation:

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