A shopkeeper sells a table at 8% profit and a chair at 10% discount thereby getting 1008. If he had sold the table at 10% profit and chair at 8% discount he would have got 20 more. Find the cost price of the table and list price of the chair.
Answers
Answer:
Step-by-step explanation:
Given,
Profit on table =8%
Discount on chair =10%
Let
C.P. of table = Rs x and
C.P. of chair = Rs y
Then according to the question,
100
x×(100+8)
+
100
y×(100−10)
=1008
⇒108x+90y=100800
⇒6x+5y=5600 … (i)
And,
100
x×(100+10)
+
100
y×(100−8)
=1008+20
⇒110x+92y=102800
⇒55x+46y=51400 … (ii)
Now, multiplying (i) by 55 and (ii) by 6, we have
330x+275y=308000 ... (iii)
330x+276y=308400 ... (iv)
Subtracting equation (iv) from (iii), we get
−y=−400
⇒y=400
On substituting the value of y in equation (i), we get
6x+5(400)=5600
⇒6x=5600−2000
⇒x=
6
3600
⇒x=600
Hence,
Cost Price of the table = Rs 600
List price of chair =400×
100
90
= Rs 360
Answer:
GIVEN
☄️case1
profit on table = 8%
discount on chair= 10%
money he received= Rs. 1008
☄️case 2
profit on table= 10%
discount on chair= 8%
money he received= 1008 + 20= Rs. 1028
To find
cost price of the table and the list price of the chair.
Solution
let the cost price of the table be Rs. X and ,
the cost price of the chair be Rs y.
According to the question:
By solving this further we get,
⇒ 108x + 90y= 108000
⇒6x + 5y= 5600 .....(i)
And,
⇒ 110x + 92y = 102800
⇒ 55x + 46 y= 51400. ....(ii)
By solving equation (i) and (ii) with elimination method we get
⇒ y = 400
Now by substituting the value of y in equation (i) we get,
6x + 5 x 400 = 5600
⇒ 6x = 5600- 2000
⇒ x= 3600/6
⇒ x= 600
Hence,
Hence, Cost Price of the table = Rs 600
List price of the chair=