Question

A shopkeeper sells two quality of tea at rate of Rs. 33 per kg. and Rs. 30 per kg, gaining 10%
and 20% profit respectively. If he mixes the two variants in the ratio 3:2 and sells the mixture at
Rs. 21 per kg., what is his gain or loss?

Answer 1

Step-by-step explanation:

the answer in pictures.. ..

Answer 2

Answer:

➡️ On the $11, he gains 10% profit.

Let the cost price be x.

So, x + 10/100 * x = 11

Or, x + x/10 = 11

Or, 11x/10 = 11

Or, x = 10.

So, cost price of the first quality of wheat is $10. ⬅️

➡️ On the $24, he gains 20% profit.

Let the cost price be y.

So, y + 20/100 * y =24

Or, y + y/5 = 24

Or, 6y/5 = 24

Or, y = 24 * 5/6 = 20.

So, the Cost price of second quality of the wheat is $20. ⬅️

He mixes them is the ratio 2 : 3.

Now, sum of ratios is = 5.

Thus, 2/5 part is the wheat of first quality and 3/5 part is the wheat of second quality.

Thus, Cost price of the mixture

= $ (2/5 * 10 + 3/5 * 20)

= $ (4 + 12)

= $ 16.

➡️ Again, the shopkeeper sells it at $12.8 per kg.

So, it is obvious that Cost price > Selling price, so there is a loss.

Loss = $ (16 - 12.8)

= $ 3.2

Now, Loss percentage

= 3.2/16 * 100 %

= 1/5 * 100 %

= 20 %

➡️ Hence, there is a loss of 20%