Question

a shopkeeper sold two articles each for rupees 1560 he secured 20% profit on first and 30% profit on other. what was the total cost price of both the articles.
( if you know then only you say)
plz tell fast ​

Answer 1

Answer:-

S.P. of one article = rs 1560

Profit % = 20%

C.P. = ?

C.P. = 100/ (100+ profit % ) × S.P.

=> 100/100+20 × 1560

=> 100/120× 1560

=> 1300

C.P. of one article is 1300

_________________

S.P of other articles = rs 1560

Profit % = 30%

C.P. = ?

C.p. = 100/ ( 100+profit% ) × S.P

=> 100/100+30 × 1560

=> 100/130×1560

=> 1200

C.P of other articles is 1200

Total C.P of both articles

=> 1300 + 1200

=> rs 2500

hope its helps you

Answer 2

Question

A shopkeeper sold two articles each for rupees 1560 he secured 20% profit on first and 30% profit on other. what was the total cost price of both the articles.

Solution

SP of fist article = ₹1560

Profit = 20%

Let, CP be x

ATP

$1560 - x = \frac{20x}{100} \\ = )1560 = \frac{20x}{100} + x \\ = ) \: 1560 = \frac{20x +100x }{100} \\ = ) \: 1560 = \frac{120x}{100} \\ = ) \: 1560 \times 100 = 120x \\ =) \: \frac{156000}{120} = x \\ = ) \: 1300 = x$

SP of second article = ₹1560

Profit = 30%

Let, CP be y

ATP

$1560 - x = \frac{30x}{100} \\ = )1560 = \frac{30x}{100} + x \\ = ) \: 1560 = \frac{30x +100x }{100} \\ = ) \: 1560 = \frac{130x}{100} \\ = ) \: 1560 \times 100 = 130x \\ =) \: \frac{156000}{130} = x \\ = ) \: 1200 = x$

Total Cost Price = ₹(1300+1200)

= ₹2500