A shopkeeper sold two tables for rupees 1485 each on one he gains 10% and on other he lost 10% gain or loss in the whole transaction
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Answer:
Profit=1485-1350= ₹135 . let the cost of one table which loss 10% be y. Loss=10/100(y) =0.1y. So selling price of the table =y-0.1y=0.9y=1485=> y=14850/9= ₹1650.
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S O L U T I O N :
A shopkeeper sold two tables for Rs.1485 each on one he gains 10% & on other he lost 10% .
- Selling price of one table, (S.P) = Rs.1485
- Gain on a table, (P) = 10%
- Cost price = ?
Using formula of the cost price when given profit;
A/q
- Selling price of other table, (S.P) = Rs.1485
- Loss on a table, (L) = 10%
- Cost price = ?
Using formula of the cost price when given loss;
Now,
Total Selling price for both tables = Rs.1485 + Rs.1485 = Rs.2970 .
Total Cost price for both tables = Rs.1350+ Rs.1650 = Rs.3000 .
S.P. < C.P.
→ Loss = Cost price - Selling price
→ Loss = Rs.3000 - Rs.2970
→ Loss = Rs.30
As we know that formula of the loss%;
→ Loss% = 30 × 100 / 3000
→ Loss% = 3000/3000
→ Loss% = 1%
Thus,
The loss in whole transaction will be 1% .
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