Math, asked by NotDonaldTrump, 2 months ago

A shopkeeper weighs 10% more while purchasing and weighs 10% less while selling. His
gain% by this dishonesty is?​

Answers

Answered by Ankur12123
4

Answer:

A shopkeeper weighs 10% more while purchasing and weighs 10% less while selling. His

gain% by this dishonesty is?

Answered by komal555
2

Answer:

Solution 1

Let cost price of

1

gm of goods

=

Rs.

1

Suppose he purchases

100

gm of goods. Total cost price

=

Rs.

100

Due to the false weight (

10

%

more), he actually gets

110

gm of goods.

Suppose he sells this

110

gm of goods.

Due to the false weight(

10

%

less), he pretends as selling

x

gm of goods.

x

×

90

100

=

110

x

=

110

×

100

90

=

1100

9

gm

Therefore he manged to get total selling price of

Rs.

1100

9

Gain

=

Rs.

1100

9

Rs.

100

=

Rs.

200

9

Gain percent =

(

200

9

)

×

100

100

=

200

9

%

=

22

2

9

%

Solution 2

Let cost price of

1

gm of goods

=

Rs.

1

Suppose he purchases

100

gm of goods. Total cost price

=

Rs.

100

Due to the false weight (

10

%

more), he actually gets

110

gm of goods.

Suppose he sells

100

gm of goods. Total selling price

=

100

Due to the false weight (

10

%

less), he actually sells only

90

gm of goods.

His gain in this entire transaction is

(

110

90

)

=

20

gm

of goods.

Now think how much money he can make by selling this

20

gm

of goods.

Due to the false weight (

10

%

less), he can actually sell

x

gm where

x

×

90

100

=

20

x

=

2000

90

=

200

9

Therefore he gets

Rs.

200

9

which is his gain amount

Gain percent

=

(

200

9

)

×

100

100

=

200

9

%

=

22

2

9

%

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