Physics, asked by kavitha2740, 7 months ago

A short magnet (M = 4 x 10^-2 A-m^2) lying in a
horizontal plane with its north-pole points 37° east of north.
Find the net horizontal field at a point of the magnet 0.1m
away from it (Bh=11×10^-6T) (sin 37° = 3/5, cos 37° = 4/5)​

Answers

Answered by sssbhoj
0

Answer:

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