Question

A shot is fired horizontally from the top of a tower with a velocity of 200 m/s. If the shot hits the ground after 2 seconds. Find the height of the tower and the distance from the foot of the tower, where the shot strikes the ground.​

Answer 1

Answer:

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Answer 2

Given :

Velocity (u) = 200 m/sec

Time (t) = 2 sec

To Find :

The height of the tower and the distance from the foot of the tower, where the shot strikes the ground.​

Solution :

As the shot is fired horizontally,

Velocity in y-axis ($u_y$) = 0

Acceleration in y-axis ($a_y$) = 9.8 m/sec²

Using Kinematic equation for uniformly accelerated motion, we have,

∴    Height (H) = $u_y$t + $\frac{1}{2}$gt²

⇒    Height (H) = 0 + $\frac{1}{2}$×9.8×(2)²

⇒    Height (H) = 19.6 m

Therefore, the height of the tower is 19.6 m

Now,

Distance from the foot of the tower = ut

                                                             = 200 × 2

                                                             = 400 m

∴ The distance from the foot of the tower is 400 m