Question

a shot moving with velocity of 140 m/s collides a wooden block and comes at rest in it.if mass of block is 13 times the mass of shot then velocity of block is​

Answer 1

The velocity of the block is 10 m/s

Explanation:

Let the mass of the shot = m

Then mass of the block = 13m

Initial velocity of the shot u = 140 m/s

Initial velocity of the block = 0

Let after the collision velocity of the shot + Block be v

Then.

From conservation of linear momentum

$mu+13m\times 0=(m+13m)v$

$\implies m\times 140=14mv$

$\implies v=\frac{140}{14}$

$\implies v=10$ m/s

Hope this answer is helpful,

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