A shot put is a metallic sphere of radius 4.9 cm.If the density of the metal is 17.8 g per cm³. Find the mass of the shot put. *
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Answered by
0
Step-by-step explanation:
Radius of the shot put = 4.9 cm
Volume of the shot put = (4/3)πr3 cm3
= (4/3) x 22/ 7 x 4.9 x 4.9 x 4.9 cm3
Density of the shot put = 7.8 gm / cm3
Mass of the shot put = 7.8 x (4/3) x 22/ 7 x 4.9 x 4.9 x 4.9 gm
= 3845.44 gm
= 3.845 kg
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Answered by
1
We have, the radius of a metallic sphere (r) = 4.9 cm
∴ Volume of the sphere = 4 / 3 πr3 = 4 / 3 × 22 / 7 × 4.9 × 4.9 × 4.9
= 493.005 cm3
∵ Density of the metal used = 7.8 g/cm3
Hence, the mass of the shot - put = 493.005 × 7.8 = 3845.44
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