Math, asked by panduteja496, 10 months ago

A side of an equilateral ABC is 6cm find the side of another ∆pqr whose area is9time the area of ∆ABC

Answers

Answered by karmaan958
0

Step-by-step explanation:

Area of equilateral = (√3/4)×a² (a = side)

Area of ∆ABC

= (√3/4)×6²

= (√3/4)×36

= 9√3

Area of ∆PQR = 9 times of ∆ABC

Area of ∆PQR = 9 × 9√3

= 81√3

Side of ∆PQR (a) =

(√3/4)×a² = 81√3

a² = (81√3 × 4)/√3

a² = 81 × 4

a² = (9×9) × (2×2)

a = 9 × 2

a = 18

So, The side of ∆PQR is 18

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