Question

difference of two side always less than or equal to third side true or false​

Answer 1

Answer:

To prove: AC-AB< BC

Construction: Mark a point 'D' on AC such that the distance AB=AD

Therefore, we have to prove that AC-AD

So, we have to prove that CD < BC

Proof:

Consider triangle ABD,

since AB=AD

Since, opposite angles opposite to the equal opposite sides are always equal.

So,  

So, p = p

Now, let  

Now, using exterior angle property in triangle ABD,

Exterior angle property of a triangle states that the measure of an exterior angle is equal to the sum of the two interior angles.

(equation 1)

Now, using exterior angle property in triangle BCD,

(equation 2)

Now, by comparing equation 1 and 2,

So, y > x

BC > CD

CD < BC

AC - AD < BC  

Since, AD = AB

Therefore, AC - AB < BC

Hence, proved.

true

Answer 2

Answer:

false

Step-by-step explanation:

only less than third side

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