A side of an isoceles right angle triangle is 7cm find its hypotenuse
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By pythagoras theorem
h^2 = 7^2 + 7^2
h^2 = 49 + 49
h^2 = 98
h = √98
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IN AN ISOSCELES TRIANGLE 2 SIDES ARE SAME
OTHER SIDE IS 7
HYPOTENUSE²=SIDE²+SIDE²
H²=7²+7²
H²=49+49
H²=98
H=√98
H=7√2
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