Question

a silver wire when bent in the form of a square encloses an area of 121sq.cm.if the same wire is bent in the form of a circle.find the area of circle

Answer 1

A=S×S
121=S²
√121=S
11cm=S

Perimeter of square=4×11=44cm


C=2πr
44=2×22/7×r
44×7/44=r
7=r


A=πr²
=(22/7)×7²
=(22/7)×49
=154cm²

Answer 2

$a = s \times s \\ 121 = s \\ 121 = s \\ 11cm = s \\ perimeter \: of \: squre = 411 = 44cm \\ c = 2nr \\ 44 \times 7 \: \: \\ a = nr \\ (22 \: 7) \times 7$