A simple harmonic moving object with the equation of deviation y = 2 sin 1/12 π t, with y in meters and t in second. Compute:
A) amplitude
B) frequency
C) period
D) y within 2 seconds
Answers
Answered by
2
general equation of SIMPLE HARMONIC motion is y = Asinwt
where A = amplitude
w = anguar frequency
we also know ,
w = 2π/T
where T is time period
now ,
compare y = Asinwt and y = 2sin1/12πt
A = 2
w = π/12
(a) amplitude = 2 metre
(b) frequency :-
2π/T = π/12
T = 24 sec
frequency = 1/T = 1/24 Hz
(c) Time peoid = 24sec
(d) y = 2sin1/12πt
t = 2 Sec
y = 2sin( 1/12π ×2)
2sin(π/6) = 2× 1/2 = 1 metre
where A = amplitude
w = anguar frequency
we also know ,
w = 2π/T
where T is time period
now ,
compare y = Asinwt and y = 2sin1/12πt
A = 2
w = π/12
(a) amplitude = 2 metre
(b) frequency :-
2π/T = π/12
T = 24 sec
frequency = 1/T = 1/24 Hz
(c) Time peoid = 24sec
(d) y = 2sin1/12πt
t = 2 Sec
y = 2sin( 1/12π ×2)
2sin(π/6) = 2× 1/2 = 1 metre
Answered by
0
Answer:-
General equation of SIMPLE HARMONIC motion is y = Asinwt
where A = amplitude
w = anguar frequency
we also know ,
w = 2π/T
where T is time period
now ,
compare y = Asinwt and y = 2sin1/12πt
A = 2
w = π/12
(a) amplitude = 2 metre
(b) frequency :-
2π/T = π/12
T = 24 sec
frequency = 1/T = 1/24 Hz
(c) Time peoid = 24sec
(d) y = 2sin1/12πt
t = 2 Sec
y = 2sin( 1/12π ×2)
2sin(π/6) = 2× 1/2 = 1 metre
hope it helps
Similar questions