A simple pendullum completes one vibration in 3 seconds.If g=9.8m/square ,then what is the time period.
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2 oscillations in 5 s hence 1 oscillation in 2.5 s which is its time period
T=2π
g
l
2.5=2π
g
l
l=10×
4π
2
6.25
=1.58m
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