Question

a simple pendulum completes 420 oscillations in 2 minutes.Calculate its frequency and time period.​

Answer 1

Answer:

frequency...420/2×60

420/120=42/12

7/2=3.5

time period...1/v

1/7/2=2/7

.28

Answer 2

The frequency and time period of the simple pendulum is 3.5 Hz and 0.28 seconds.

Explanation:

Given that,

Number of oscillations is 420 in 2 minutes or 120 seconds.

To find,

Its frequency and the time period.

Solution,

Frequency is defined as the number of oscillations per unit time. So, the frequency of a simple pendulum is given by :

$f=\dfrac{420}{120\ s}$

f = 3.5 Hz

The formula of time period in terms of frequency is given by :

$T=\dfrac{1}{f}$

$T=\dfrac{1}{3.5}$

T = 0.28 seconds

So, the frequency and time period of the simple pendulum is 3.5 Hz and 0.28 seconds.

Learn more,

Wave

https://brainly.in/question/10764229