Question

A simple pendulum makes 20 oscillations in 40 seconds. What is the time period and frequency of its oscillation? NCERT Class VIII Science - Exemplar Problems Chapter 13. Sound

Answer 1

Explanation:

It is given that,

Number of oscillations made by the simple pendulum, N = 20

Time taken, t = 40 seconds

Let T is the time period of its oscillation. The total number of oscillations per unit time is called frequency of the simple pendulum. It can be calculated as :

$f=\dfrac{20}{40}\ Hz=0.5\ Hz$

The relation between the time period and frequency is given by :

$f=\dfrac{1}{t}$

$t=\dfrac{1}{0.5\ Hz}$

t = 2 seconds

Hence, this is the required solution.

Answer 2

It is given that,

Number of oscillations made by the simple pendulum, N = 20

Time taken, t = 40 seconds

Let T is the time period of its oscillation. The total number of oscillations per unit time is called frequency of the simple pendulum. It can be calculated as :

f = 40/20 hertz = 0.5 Hertz

The relation between the time period and frequency is given by :

f=1/T

T = 1/0.5

t = 2 seconds

So here is your solution.