Question

A simple pendulum makes 300 oscilations in 10 minutes find the time period and frequency of its osciallations

Answer 1

For a simple pendulum :-

Given :-

$\sf{Number \: of \: oscillations = 300}$

$\sf{Time \: \: taken = 10 \: minutes = 600 \: seconds}$

To Find :-

$\sf{Time \: period \: and \: frequency \: of \: its \: oscillations}$

Using Formulas :-

$\sf{Time \: period =\dfrac{No. \: of \: oscillations}{used \: time}}$

$\sf{Frequency =\dfrac{1}{Time \: period}}$

Solution :-

$\sf{Time \: period \: (T) =\dfrac{300}{600}}$

$\sf{T =\dfrac{1}{2} = 0.5 \: second}$

Now ,

$\sf{Frequency \: (f) =\dfrac{1}{T}}$

$\sf{f =\dfrac{1}{0.5}}$

$\sf{f =\dfrac{10}{5}}$

$\sf{f = 2 \: Hertz}$

As We got :-

$\sf{Time \: period = 0.5 \: Second}$

$\sf{Frequency = 2 \: Hertz}$