Question

A simple pendulum of length 1cm has a mass of a 10 gram and oscillates freely with amplitude 2cm find its potential energy at extrem point​

Answer 1

Answer:

ANSWER

Given L=1m

m=10g=10×10−3g

a=5cm=5×10−2m

We know that, t=2πgl & w=t2π

⇒w=2πgl2π=lg

At extreme position

PE=21mw2a2

=21mlga2

=21×110×10−3×9.8×(5×10−2)2

=0.0001225

=1.225×10−4J

∴ Potential energy at extreme position

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