Question

A simple pendulum of length l has a Bob of mass m. It is released from the horizontal position. The tension in the string at the lowest point is

Answer 1

Answer:

Tension in the string at lowest point is 3mg

Explanation:

Length of the pendulum = l

Mass of the bob = m

Let the velocity at the lowest position is v

The bob is released from the horizontal position then its potential energy will be converted into kinetic energy at the lowest position

$mgl=\frac{1}{2}mv^2$

$\implies v^2=2gl$

the centrifugal acceleration at the lowest point

$=m\frac{v^2}{l}$

$=m\frac{2gl}{l}$

$=2mg$

The tension in the string at the lowest point

= Weight of the bob + Tension due to centrifugal force

$=mg+2mg$

$=3mg$

Answer 2

Answer:

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