Question

A simple pendulum oscillates with amplitude 0.04 m. If its time period is 10 s,
calculate the maximum velocity.

Answer 1

Answer ⇒ The maximum velocity is 0.025 m/s.

Explanation ⇒ Using the formula,

Maximum velocity = ωA,

where ω is the angular frequency and A is the amplitude.

ω = 2π/T

∴ ω = 2π/10

ω = π/5

Thus,

Vmax. = π/5 × 0.04

∴ Vmax. = 0.025 m/s.

Hence, the maximum velocity is 0.025 m/s.

Hope it helps.

Answer 2

Answer:

Maximum velocity = ωA,

where ω is the angular frequency and A is the amplitude.

ω = 2π/T

∴ ω = 2π/10

ω = π/5

Thus,

Vmax. = π/5 × 0.04

∴ Vmax. = 0.025 m/s.

Explanation: