Two simple harmonic waves are represented by equations y1
= a sin (ωt –
kx) and y2
= a sin [(ωt – kx) + φ]. What is the phase difference between these
two waves?
Answers
Answered by
0
Answer ⇒ The phase difference between the two waves is φ.
Explanation ⇒ Given two waves have equations,
y₁ = a sin (ωt – kx)
Comparing this equation with the standard equation of waves,
y = ASin(ωt ± kx + φ)
we will get, Phase angle (Φ₁) = 0
y₂ = a sin [(ωt – kx) + φ]
Phase angle (Φ₂) = φ
Phase difference = φ₂ - φ₁
= φ - 0
= φ
Hence, the phase difference between the two waves is φ.
Hope it helps.
Answered by
2
Answer:
The phase difference between the two waves is φ.
Explanation:
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