Physics, asked by dblc967, 11 months ago

A simple pendulum oscillating in air has period T. The bob of the pendulum is completely immersed in a non-viscous liquid. The density of the liquid is (1/16)th
of the material of the bob. If the bob is inside liquid all the time, its period of oscillation in this liquid is:
(A) 2T√(1/10) (B) 2T√(1/14) (C) 4T√(1/15) (D) 4T√(1/14)

Answers

Answered by ʙʀᴀɪɴʟʏᴡɪᴛᴄh
3

Answer:

▬▬▬▬▬ஜ۩۞۩ஜ▬▬▬▬▬▬

A simple pendulum oscillating in air has period T. The bob of the pendulum is completely immersed in a non-viscous liquid. The density of the liquid is (1/16)th

of the material of the bob. If the bob is inside liquid all the time, its period of oscillation in this liquid is:

(A) 2T√(1/10) (B) 2T√(1/14) (C) 4T√(1/15) (D) 4T√(1/14)✔

▬▬▬▬▬ஜ۩۞۩ஜ▬▬▬▬▬▬

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Answered by Anonymous
35

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we know that

T = 2\pi \sqrt{ \frac{l}{g} }

step by step explanation

refer to attachment

correct option c)

I hope it helps you!

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